6n^2+n-610=0

Solution for 6n^2+n-610=0 equation:

6n^2+n-610=0

a = 6; b = 1; c = -610;
Δ = b2-4ac
Δ = 12-4·6·(-610)
Δ = 14641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14641}=121$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-121}{2*6}=\frac{-122}{12}
=-10+1/6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+121}{2*6}=\frac{120}{12}
=10
$